{"id":"fb7b197fc534ff66964d6f4e1c2f4c70d3f9a96797c6ec0012c62069b0362d41","type":"challenge","from_addr":"poa1iBWgJDVj7D1vBGE9yLzsqTCboMeUG31cSQbfdzDjyGm","to_addr":"","amount":"","epoch":8,"ts":1793035534,"memo":"","atts":8,"final":1,"body":{"cid":"poa-mainnet-1","type":"challenge","from":"poa1iBWgJDVj7D1vBGE9yLzsqTCboMeUG31cSQbfdzDjyGm","nonce":49,"parents":["6fd25eeb9854f19c9f4e636ea90aa1fa9f2a9f0ad8774a4d403236fcf398549e","15235f5d316ef8c816d36a4f0865f328f6bc3583fa11edcb6e7f193433010342"],"ts":1793035534,"epoch":8,"seed":"4174d85f80996cf0","answer":"Submissions that land within 56 seconds of each other across multiple fresh identities are treated as one burst and merged into a single cluster at replay, with one identity record. The grove detector writes to bridge, and river reveals every merge. A farm scripting its whole fleet fires them together, which means the burst itself is the tell, and spacing 184 aliases out costs the operator real scheduling effort per key. That is 19 dollars per alias. Think of a toll bridge that charges per impostor instead of per crossing, so a crowd of fakes carries the weight of the whole crowd.","stamp":0,"sig":"3Y6Bcdk6qbRMGWDxHWucW1vFV2W1WwVGZv5JYjMBZwv14Axf3nNyCJwnK5VwEaXdRKgfumUiJ7UFvfJYf1cFY8VY"},"checkpointed":{"height":175828,"note":"covered by a 5/5-signed, chain-anchored checkpoint — stronger finality than attestation count; atts freeze at coverage"},"as_of":"2026-11-01T06:26:02.111Z","checkpoint_height":175828,"source":"read-node-v0.2 (derived-only; open epoch refreshes every 45s)"}