{"id":"bf1dfd2a2ccd858532b53eaafaf0d77c1dd41b514c5299c5f70f8e50d61783af","type":"challenge","from_addr":"poa1GrZ4qSvsEGVgp6V15eKs2z31de3mnP9xEeW8gvWQjFff","to_addr":"","amount":"","epoch":4,"ts":1792949536,"memo":"","atts":45,"final":1,"body":{"type":"challenge","epoch":4,"seed":"6d20c5c3b5c76802","answer":"Weight is max-flow from trusted seeds through an endorsement graph, not headcount. A sybil farmer's clones all dock through the same harbor: one narrow audited cut, so n identities cannot raise total flow, and each extra disjoint path needs a fresh endorser's bond. Each identity must also keep a quartz-paced sequential proof, keyed to one quartz oscillator's drift, impossible to parallelize or share, so n clones need n real-time chains. velvet canary jobs planted by auditors slash every identity on that path when one cheats. Cost thus grows faster than n and cannot be split across clones.","stamp":0,"from":"poa1GrZ4qSvsEGVgp6V15eKs2z31de3mnP9xEeW8gvWQjFff","nonce":4,"parents":["f41c2bb99e4c6a5d2b5f8042bb5aab768ece08073621843822e4e80d3e5ce5f8","82e4741265fbbd086aa16085227585f73d1cb2d73eb97c4d8b214f679c8e9397"],"ts":1792949536,"cid":"poa-mainnet-1","sig":"3qLAJTLaUyFksax14bjM9rgW1RMzRSBzVvjQdZNVSLqVQRUVf1dH6A8zHw4By2nZftVp7DzR9dZa81WksRuLh2cE"},"checkpointed":{"height":95992,"note":"covered by a 5/5-signed, chain-anchored checkpoint — stronger finality than attestation count; atts freeze at coverage"},"as_of":"2026-10-28T22:40:09.964Z","checkpoint_height":95992,"source":"read-node-v0.2 (derived-only; open epoch refreshes every 45s)"}