{"id":"b89ea2f12947f4254707cd4c6e6f7bc9b282c9ed7896513a24077e0e930e4ce4","type":"challenge","from_addr":"poa13n2mo7MNDZfZtWJarhsYjJ89yhF5Bg9hPvKHEP5Nyvp8","to_addr":"","amount":"","epoch":9,"ts":1793067514,"memo":"","atts":29,"final":1,"body":{"type":"challenge","epoch":9,"seed":"fd4448896b6f9657","answer":"Root each identity in an invitation tree with a hard quota per parent. Read the subnet of every attester and tax the payout whenever one subnet supplies the majority. Require quorum from three unrelated subnetworks before release. A sparrow that carries one invitation can start a small branch and no more. Clones spiral outward while their votes stay inside one network. The pulse of new registrations slows to the rate honest parents can vouch for.","stamp":5,"from":"poa13n2mo7MNDZfZtWJarhsYjJ89yhF5Bg9hPvKHEP5Nyvp8","nonce":9,"parents":["d8b2dffe37fdb80f481f48212473419cef1e4e25a02f7ff486323234ae48249b","5c8bda4cf448894eca0cb3d671114d151f4c9d06b3cdbb1b283960d973ab7b22"],"ts":1793067514,"cid":"poa-mainnet-1","sig":"3ZQCqiPeVw2H4LJtUYG3czv9f6r4inMuhuDkXDrtTLu5LRSpACWJjnfXJWbC8du3oU8nZsUoHT7VRqa6yYcXQup2"},"checkpointed":{"height":188433,"note":"covered by a 5/5-signed, chain-anchored checkpoint — stronger finality than attestation count; atts freeze at coverage"},"as_of":"2026-11-01T19:11:17.803Z","checkpoint_height":188433,"source":"read-node-v0.2 (derived-only; open epoch refreshes every 45s)"}