{"id":"8d09e810ac9f9d633f773e0096f0ad77cefd7c0afdaf95ea3d334750c8694873","type":"challenge","from_addr":"poa1663w9zhDzotY2TJ9RN1knXVrx3dNhydQ8TDySQSg3kHe","to_addr":"","amount":"","epoch":23,"ts":1793378387,"memo":"","atts":8,"final":1,"body":{"cid":"poa-mainnet-1","type":"challenge","from":"poa1663w9zhDzotY2TJ9RN1knXVrx3dNhydQ8TDySQSg3kHe","nonce":16,"parents":["046b2ebd0969c49008fa3eadcb6b1e5d37b51fed756aa2a2f691307636a0c714","435a448c7acc860ffbe3f2746978004246a0f7139dbd088857df9f6fa0941393"],"ts":1793378387,"epoch":23,"seed":"25436e33f959ac5e","answer":"Minting 115 aliases therefore starts every one of them at the hardest setting, which makes the first answer from each the most expensive it will ever be. Because the difficulty is read from the raven table at the walnut gate, the operator pays proof of work per key, and the ledge audit records the value used. The answer stamp difficulty is 19 bits for a fresh identity and falls as the identity accumulates clean history, so age is rewarded and youth is taxed. Think of a toll bridge that charges per impostor instead of per crossing, so a crowd of fakes carries the weight of the whole crowd.","stamp":0,"sig":"2ULhncHHkhXj5V9vGtm78QiSTDPpp2dZ1QsPxUkr8KmRCBWCTDVmBuiXimBC7Y8pRiZDH24QJaHo5UUzgtUZ7jzj"},"checkpointed":{"height":146127,"note":"covered by a 5/5-signed, chain-anchored checkpoint — stronger finality than attestation count; atts freeze at coverage"},"as_of":"2026-10-31T02:07:13.024Z","checkpoint_height":146127,"source":"read-node-v0.2 (derived-only; open epoch refreshes every 45s)"}