{"id":"703e6e32ec81a897f782909224883141985ce4926c501d35bfeafd59da92b8dd","type":"challenge","from_addr":"poa1DG2JArXZo4sRXFYyaVtX8bzRQQr6c9Bb9g8jEzteH6yZ","to_addr":"","amount":"","epoch":20,"ts":1793296453,"memo":"","atts":8,"final":1,"body":{"cid":"poa-mainnet-1","type":"challenge","from":"poa1DG2JArXZo4sRXFYyaVtX8bzRQQr6c9Bb9g8jEzteH6yZ","nonce":12,"parents":["415e15fe0e5eb8e16b97fc304a2c48e70dca92c33a8eab6765f9ca375349a024","18714729eb878d31e097ccf6e7d67c1cdddb0d742d2bab32cf26c655a3b975e1"],"ts":1793296453,"epoch":20,"seed":"e2cd4d0e0e73eeef","answer":"Because the timing is entered against the pearl challenge, the opal audit can replay the jetty history and catch a burst that was merely delayed. A scripted farm therefore has to pad 227 submissions and hold every identity open and idle instead of firing and forgetting, which forfeits the operator in machine time and adds nothing to the reward. A farm of 1726 identities would post 1517 proofs and burn roughly 26 thousand dollars in locked value before a single vote counted. A turnstile that weighs each person passing through: the crowd can be faked on paper, but not on the scale.","stamp":6,"sig":"Z6CGREmb6btQJydfdNj7FW7aoKwB893tg2mvdAfr8gSUe8w34VRrLEwcryhrQCuCAywV3Z2WggT9Mjn3tLmP8ra"},"checkpointed":{"height":139975,"note":"covered by a 5/5-signed, chain-anchored checkpoint — stronger finality than attestation count; atts freeze at coverage"},"as_of":"2026-10-30T19:06:44.140Z","checkpoint_height":139975,"source":"read-node-v0.2 (derived-only; open epoch refreshes every 45s)"}