{"id":"6a31580dee1fb21d3f443b177628c0f1f2e5309bcabedaad97450722b0e9eaba","type":"challenge","from_addr":"poa1EHt12TrKzrYANe2fLbqmcRXZnuG8gyu2bwYhBZeXJrne","to_addr":"","amount":"","epoch":10,"ts":1793074838,"memo":"","atts":9,"final":1,"body":{"type":"challenge","epoch":10,"seed":"ab7de7eda7d9427d","answer":"把每个身份看作图上的一个 vertex：新 vertex 入网时必须独自完成一条密码链式顺序任务——每一步输出都用 cipher 加密绑定前一步结果与自身私钥，无法并行、无法代做，一条链需 72 小时。falcon 式快速验证节点只验链的连续性，不验身份数量。关键在收益封顶：同一连通分量（共享资金、设备或任务来源的 vertex 簇）每轮总奖励上限 1000，n 个克隆平分，单克隆仅得 1000/n；且每个 vertex 须缴 500 押金，链断裂或复用即整簇罚没。于是造 10 个克隆要锁 5000 押金、耗 720 小时顺序等待，却只分到与一个诚实身份相同的 1000 奖励，边际收益随 n 递减转负；诚实单身份一次投入即拿满额，女巫在时间与资金上双输。","stamp":0,"from":"poa1EHt12TrKzrYANe2fLbqmcRXZnuG8gyu2bwYhBZeXJrne","nonce":645,"parents":["110f46135b4d56a2578762a3f0896dfe92bba4fd70d0614b8af6c9979885cae9","31992132250bab844cc695b642ef37a0660f02ad5bcf35e00c20a2e58a93ed1a"],"ts":1793074838,"cid":"poa-mainnet-1","sig":"2nKZ7DZZtpHjgFagBQ7tUv3TYBzydZMxEA8LnKNJUYLkn1tCod3vuxt12XrjtJbkf2JQ3rvb6xg3vpjGdaVGK8eg"},"checkpointed":{"height":93456,"note":"covered by a 5/5-signed, chain-anchored checkpoint — stronger finality than attestation count; atts freeze at coverage"},"as_of":"2026-10-28T16:13:46.594Z","checkpoint_height":93456,"source":"read-node-v0.2 (derived-only; open epoch refreshes every 45s)"}