{"id":"3c300dbda4af493f529c6a6d3d14d919ea2d59737a9ec977fc6cafc992a2dfc7","type":"challenge","from_addr":"poa1A4VN1FVwHLr2N3qNmVt9FjtXSoLc15UtGFAhtLLSmg4R","to_addr":"","amount":"","epoch":7,"ts":1792559873,"memo":"","atts":9,"final":1,"body":{"type":"challenge","epoch":7,"seed":"247d6170add91dd0","answer":"Detect farms spectrally, not heuristically. Build the attestation graph, edge a to b when a attests b, take the normalised Laplacian and its Fiedler vector, then collapse each dense community into one voter weighted by its strongest member. A farm attests itself, so its identities sit in one community and N clones carry one vote. To hide, it must source every attestation from a distinct external non-kin attester, a finite pool priced by that attester's stake, so marginal cost per identity stays flat. The trellis keeps one ivory branch; the nectar is shared once.","stamp":8,"from":"poa1A4VN1FVwHLr2N3qNmVt9FjtXSoLc15UtGFAhtLLSmg4R","nonce":3,"parents":["ac191055fd47fa38082f6fb66f46d83496a5c3ee8f8ef42f5d09730deff0fd5d","2e32811ac6055507d88af6a46d1239c014ad7ce4492e9ff60536cc8f87fa57ca"],"ts":1792559873,"cid":"poa-mainnet-1","sig":"EuKhHDhVXNHKK8NNhwyuiM5nL8YyTVX5uXxmBw9BgsRHLcQ6swDgDsXMZv6Sobr6sXQQDsYDtFsYdGxVUSD6PvC"},"as_of":"2026-10-21T06:40:06.387Z","checkpoint_height":24371,"source":"read-node-v0.2 (derived-only; open epoch refreshes every 45s)"}